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BabaBlast [244]
3 years ago
7

Correct the formula Please

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer:

The addition should be divided by 4 and not 3 since there are 4 meals.

Step-by-step explanation:

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Solve the Linear Quadratic system of equations<br><br> y=x^(2)+2x-9<br> y=-2x+3
Debora [2.8K]

9514 1404 393

Answer:

  (x, y) = (-6, 15) and (2, -1)

Step-by-step explanation:

You can start by subtracting the second equation from the first.

  (y) -(y) = (x^2 +2x -9) -(-2x +3)

  0 = x^2 +4x -12 . . . . . . collect terms

  0 = (x +6)(x -2) . . . . . . . factor

Solutions for x are -6 and +2. These values make the factors zero.

The corresponding solutions for y are ...

  y = -2(-6) +3 = 15

  y = -2(2) +3 = -1

Solutions to the system of equations are ...

  (x, y) = (-6, 15) and (2, -1)

3 0
2 years ago
Look at the sample space below.
Jobisdone [24]

Answer:

There are 10 odd numbers: {1, 3, 5, 7, 9, 11, 13, 15, 17, 19} There are 4 factors of 8: {1, 2, 4, 8} There is 1 number in both lists: {1} Probability of an odd or a factor of 8 = (10 + 4 - 1)/20 = 13/20

5 0
2 years ago
#9 please it’s very hard @HavannaS
Marrrta [24]
I don't know if this is right or not but I think the coordinates at the angle on the circular protractor so for a) if you (114-62) you should get the answer, for b)if you (62+40) you should get the answer, for c) if you [114-(62+40)] you should get the answer.
5 0
3 years ago
Write an equation for the line parallel to the given line that contains C.<br> Help
tangare [24]
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6 0
3 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
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