Just one. Hope this helps!
We can solve this quadratic equation using factorisation method as follows
:x2−5x−36=0
x2+4x−9x−36=0
x(x+4)−9(x+4)=0
(x+4)×(x−9)=0
x+4=0orx−9=0
x=−4orx=9
Answer:
π + 2
Step-by-step explanation:
x² + y² - 4x - 4y + 4 = 0
(x² - 4x + 4) + (y² - 4y + 4) + 4 - 4 - 4 = 0
(x - 2)² + (y - 2)² = 4
So the radius of the circle = 2, center C(2, 2)
Are a of AMNB = area of semi-circle - area of segment AB
= area of semi-circle - (area of quarter circle ABC - area of triangle ABC)
= area of quarter circle ABC + area of triangle ABC
= π(2)²/4 + 2*2/2
= π + 2