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Diano4ka-milaya [45]
3 years ago
15

The cost function for a certain company is C = 40x + 800 and the revenue is given by R = 100x − 0.5x2. Recall that profit is rev

enue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $800.
Mathematics
1 answer:
galina1969 [7]3 years ago
3 0
In order to do this, you have to find your profit equation and then set it equal to 800, which is the profit you're seeking.  when you subtract the cost from the revenue, the new equation (or the profit equation) is this:
 p(x)= -.5x^2 + 60x -800.  If you want your profit, p(x), to be $800, then you set your equation equal to 800 and solve it for x, the 2 values that will bring about that 800 profit. Those production levels, or values for x, are -22.5 and 142.5  Since you cannot have a negative production level, you need to produce 142.5 whatevers to make that profit.
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slega [8]

Answer:

135 meters

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h = 60t - 5t²

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Sub the value '3' into 't'

h = 60(3) - 5(3)²

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3 years ago
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Studentka2010 [4]
Well, let's just solve all these darn operations!

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2 years ago
At the beginning of year 1, Sam invests $700 at an annual compound interest
Aleksandr-060686 [28]

at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$700\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=\textit{elapsed years}\dotfill &3 \end{cases}

A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill

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2 years ago
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Bingel [31]

Step-by-step explanation:

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Total marks for the class = 60 * 30 = 1800.

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Mean mark for the boys = 720 / 10 = 72.

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