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Snowcat [4.5K]
3 years ago
15

Can you draw a triangle with angles 90°45° 75° yes or no

Mathematics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

90,45 and 75°-acute angle-an angle between 0 and 90 degrees. right angle-an 90 degree angle.

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The interest rate is 0.4833333%
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Find three consecutive integers whose sum is negative 21
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-6,-7, and -8, this is more of a guess and check question

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3 years ago
Find the probability of rolling a sum of 6 with two dice?
34kurt

Answer: 5/36

Step-by-step explanation:

There are 3 ways to do this

Get a 1 and a 5

Get a 2 and a 4

Or get two 3's.

There are two ways to get a 1 and a 5

1 first and 5 second or

5 first and 1 second

The same goes for the 2 and the 4, but NOT for the two 3s.

We have 5 ways to get a sum of 6

What is the probability of one of them happening?

1/6 x 1/6 = 1/36

1/36 chance of one occuring

1/36 x 5 = 5/36 chance of getting a sum of 6 (as there are 5 ways to do so)

8 0
4 years ago
What is the greatest number that has one comma when written with numerals and with number names
kumpel [21]
<span>The greatest number that has one comma when written with numerals and with number names is 999,999

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6 0
3 years ago
Read 2 more answers
when a card is drawn from a standard deck of 52 cards, what is the probability of getting a. queen b.a red. c.a queen or a red c
Brut [27]

(a) Probability of getting a queen from a deck of 52 cards = \frac{1}{13}

(b) Probability of getting a red card from a deck of 52 cards = \frac{1}{2}

(c) Probability of getting a queen or a red card from a deck of 52 cards = \frac{7}{13}

<u>Solution:</u>

Given that card is drawn from a standard deck of 52 cards.

Need to determine probability of getting  

(a) queen (b) red (c) a queen or a red card

\text { Probability of an event }=\frac{\text { favorable number of events }}{\text { total number of events }}

<em><u>(a) Calculating probability of getting a queen from a deck of 52 cards </u></em>

Favorable events are getting a queen of spade, heart , diamond or club.

Means number of favorable events = 4

Total events is all possible outcomes from 52 cards  

So Total number of event = 52

\Rightarrow \text { probability of getting a queen }=\frac{4}{52}=\frac{1}{13}

<em><u>(b) Calculating probability of getting a red card from a deck of 52 cards </u></em>

Number of red cards are 13 cards of diamonds and 13 cards of heart = 13+13 =26

So number of favorable event = 26

Total number of event = 52

\Rightarrow \text { probability of getting a red card }=\frac{26}{52}=\frac{1}{2}

<em><u>(c) Calculating probability of getting a queen or red card from a deck of 52 cards </u></em>

Favorable events are 26 red cards + two queens of spade and club. Need to keep in mind that queens of heart and diamond is already considered in 26 red cards.

So number of favorable event = (26+2) = 28

Total number of event = 52

\text { Probability of getting a queen or red card }=\frac{28}{52}=\frac{7}{13}

<em><u>Summarizing the result :</u></em>

(a) Probability of getting a queen from a deck of 52 cards = \frac{1}{13}

(b) Probability of getting a red card from a deck of 52 cards = \frac{1}{2}

(c) Probability of getting a queen or a red card from a deck of 52 cards = \frac{7}{13}

7 0
4 years ago
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