2.5 b = 27.5
b = 27.5 / 2.5
b = 11
So, 3 boxes x 10 markers=
30 markers/ 5=
6 markers each person will get.
Answer:
Hence the expression ![$$(5x-y)(x-4)=5x^2-xy-20x+4y$$](https://tex.z-dn.net/?f=%24%24%285x-y%29%28x-4%29%3D5x%5E2-xy-20x%2B4y%24%24)
Step-by-step explanation:
Explanation
- The given expression is (5 x-y)(x-4).
- We have to multiply the given expression.
- Multiply the (5 x-y) by -4, multiply the (5 x-y) by x then add like terms.
![$$\begin{matrix}{} & {} & {} & {} & 5x & - & y \\ \times & {} & {} & {} & x & - & 4 \\ \end{matrix}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Bmatrix%7D%7B%7D%20%26%20%7B%7D%20%26%20%7B%7D%20%26%20%7B%7D%20%26%205x%20%26%20-%20%26%20y%20%5C%5C%20%5Ctimes%20%26%20%7B%7D%20%26%20%7B%7D%20%26%20%7B%7D%20%26%20x%20%26%20-%20%26%204%20%5C%5C%20%5Cend%7Bmatrix%7D%24%24)
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![$$\begin{matrix}{} & {} & {} & - & 20x & + & 4y \\ 5{{x}^2} & - & xy & {} & {} & {} & {} \\ \end{matrix}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Bmatrix%7D%7B%7D%20%26%20%7B%7D%20%26%20%7B%7D%20%26%20-%20%26%2020x%20%26%20%2B%20%26%204y%20%5C%5C%205%7B%7Bx%7D%5E2%7D%20%26%20-%20%26%20xy%20%26%20%7B%7D%20%26%20%7B%7D%20%26%20%7B%7D%20%26%20%7B%7D%20%5C%5C%20%5Cend%7Bmatrix%7D%24%24)
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![$$\begin{matrix}5{{x}^2} & - & xy & - & 20x & + & 4y \\ \end{matrix}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Bmatrix%7D5%7B%7Bx%7D%5E2%7D%20%26%20-%20%26%20xy%20%26%20-%20%26%2020x%20%26%20%2B%20%26%204y%20%5C%5C%20%5Cend%7Bmatrix%7D%24%24)
![\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cfrac%7Bx%2B2%7D%7Bx%5E2%2B2x-3%7D%7D%7B%5Cfrac%7Bx%2B2%7D%7Bx%5E2-x%7D%7D)
If
, then we can immediately cancel the factors of
:
![\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cfrac1%7Bx%5E2%2B2x-3%7D%7D%7B%5Cfrac1%7Bx%5E2-x%7D%7D%3D%5Cdfrac%7Bx%5E2-x%7D%7Bx%5E2%2B2x-3%7D)
Factorize the numerator and denominator:
![x^2-x=x(x-1)](https://tex.z-dn.net/?f=x%5E2-x%3Dx%28x-1%29)
![x^2+2x-3=(x+3)(x-1)](https://tex.z-dn.net/?f=x%5E2%2B2x-3%3D%28x%2B3%29%28x-1%29)
Next, if
, then
![\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E2-x%7D%7Bx%5E2%2B2x-3%7D%3D%5Cdfrac%7Bx%28x-1%29%7D%7B%28x%2B3%29%28x-1%29%7D%3D%5Cdfrac%20x%7Bx%2B3%7D)
Answer:
it will be
Step-by-step explanation:
6/9 but a mix number i don't know