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Roman55 [17]
3 years ago
10

What is the sum of −3x+6−3x+6 and 7x−87x−8 ?

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
-86x + 4 for the original answer
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Need help can someone explain to me the steps how you got it is need to understand it
olga2289 [7]
Justin's statement would be the best. In order to change 3/5 into 6/10, both sides would need to be multiplied by 2.
7 0
2 years ago
) Asuka travels at an average speed of 50 mph for 20 miles.
Anuta_ua [19.1K]

Answer: 41.86 miles/hour

Step-by-step explanation:

Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [<em>in brackets</em>].

MPH MILES     HOURS

 50            20      [<em>0.4]</em>

 [<em>40</em>]    <u>70</u>      <u>1.75</u>

Totals   90 miles   2.15 hours

Average = 90 miles/2.15 hours

     41.86 mph

5 0
2 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
What is the fraction for 45 divided by 20 please show work
lianna [129]

Answer:

9/4

Step-by-step explanation:

The divide symbol is also the line that separates the numerator and the denominator, so 45÷20 can also be written as 45/20.

We can see that both 45 and 20 are divisible by 5, so we can simplify the fraction down to 9x5/4x5, and then we cancel out the 5s and are left with 9/4

4 0
3 years ago
Gonna need help answering this <br> Y=1/2x+7<br> Y=x-8
Nata [24]
What is the problem?
3 0
3 years ago
Read 2 more answers
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