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2 years ago

7

Leila's company makes solid metal balls for various industrial uses. A customer wants lead balls that have a diameter of 6 in. I

f Leila must make 80 of these balls, how much lead will she need?
Use 3.14 for Pi, and do not round your answer.

1 answer:

MakcuM [25]2 years ago

5 0

Answer:

9043.2 in^3 of lead

Step-by-step explanation:

the formula is (4/3)(3.14)r^3

so,

(4/3)(3.14)(3^3) * 80

9043.2

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