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Brut [27]
3 years ago
10

Which of the following is the quotient of the rational expressions shown below?

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0
Find the attached picture.

gayaneshka [121]3 years ago
6 0
The given fraction involves two Rational Expressions, one in numerator and one in denominator.

The rational expression in the denominator can be multiplied to the numerator after taking its reciprocal, this will help to simplify the expression as shown below:

\frac{ \frac{5x}{2x+3} }{ \frac{x+1}{3x} } \\  \\ 
= \frac{5x}{2x+3} * \frac{3x}{x+1}  \\  \\ 
= \frac{15 x^{2} }{(2x+3)(x+1)}

There are no common factors in the numerator and the denominator so the expression cannot be simplified any further.


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The set of ordered pairs below represents a linear function.
Doss [256]
Pretty sure ( -2,-7) because from -1 you go over one then each y is going down 3 so -4 - 3 is -7
8 0
3 years ago
Will mark brainliest and 15 points
insens350 [35]

Answer:

Step-by-step explanation:

x - 3y  -15

x = -3

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Sample size: A researcher is trying to decide how many people to survey. Which of the following sample sizes will result in a co
oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given that a researcher is trying to decide how many people to survey.

We have confidence intervals are intervals with middle value as the mean and on either side margin of error.

Confidence interval = Mean ± Margin of error

Thus confidence interval width depends on margin of error.

Margin of error = Critical value *\frac{\sigma}{\sqrt{n} }

Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.

Hence for small n we get wide intervals.

So if sample size = 300, the researcher will get wider confidence interval

4 0
3 years ago
A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla
Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

\frac{4}{12} * \frac{8}{11} =   \frac{32}{132} or 0.2424 or 24.24%

8 0
3 years ago
The difference of two numbers is 8. When twice the first number is added to three times the second number, the result is 51. Wha
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2 years ago
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