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ella [17]
3 years ago
7

PLEASE I NEED AN ANSWER NOW JUST PLEASE I WILL GIVE BRAINLIEST TO THE FIRST CORRECT ON

Mathematics
1 answer:
Doss [256]3 years ago
3 0

Answer: It C

Step-by-step explanation: Proportional relationships are relationships between two variables where their ratios are equivalent.

On That Problem Its Equivalent, so Its C.

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Anastasy [175]
Are you doing FLVS? IF so I need hep
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3 years ago
Which inequality is shown in this graph
Katena32 [7]

ANSWER

y \leqslant   - 2x - 2

EXPLANATION

The boundary line passes through (-2,2) and (0,-2).

The slope of this line is

m =  \frac{ - 2 - 2}{0 -  - 2}

m =  \frac{ - 4}{2}  =  - 2

The y-intercept is , c=-2.

The slope-intercept form of this line is given by;

y = mx + c

We substitute values to obtain;

y =  - 2x - 2

Since the lower half-plane is shaded the required inequality is

y \leqslant   - 2x - 2

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3 years ago
Find a polynomial with zeros at x=2,x=-1 and x=0
Amiraneli [1.4K]

Answer:

f(x) = x^3 - x^2 -2x

Step-by-step explanation:

If x = a is a zero of a polynomial, then x-a is a factor of the polynomial. Given the factors of a polynomial, the polynomial can be obtained by multiplying the factors.

The factors of the given polynomial are;

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Multiplying the first two factors;

(x-2)(x+1) = x^2 + x -2x -2

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We finally multiply this result by x to obtain our polynomial;

f(x) = x ( x^2 -x -2)

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which is a cubic polynomial since it has 3 roots.

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Read 2 more answers
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~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2 - 9\qquad \textit{we also know that} \begin{cases} x=2\\ y=-7 \end{cases} \\\\\\ -7=a(2-1)^2-9\implies 2=a(1)^2\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} y=2(x-1)^2 -9 \end{array}} ~\hfill

6 0
1 year ago
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