Question

-Let g(x) be a function defined by g(x) = x3.

Answer 1

Answer:

Step-by-step explanation:

a) The graph rises steeply from the third quadrant  and there is a point of inflection through  the origin (0, 0) then rises steeply in quadrant 1.

b) Let y = g(x) = x^3

x = ∛y

So g(-1)x = ∛x.

The graph is the reflection of g(x) in y = x.

c) Domain of g(x) = All real x, Range is all real g(x).

Domain of  g(-1)x  = All real x, Range = all real g-1(x).

d) You will see the end behaviour from the graphs.

I tried to send you a link to the graphs but the system wont allow it.