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3 years ago

13

Which of the following best describes the equation below? A. linear B. both linear and nonlinear C. neither linear nor nonlinear

D. nonlinear

1 answer:

Julli [10]3 years ago

4 0

Answer:

Where is the equation at

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A coupon subtracts $17.95 from the price p of a pair of headphones. You pay $71.80 for the headphones after using the coupon. Wr

omeli [17]

71.80 - 17.95 = 53.85

6 0

3 years ago

A circle with a radius of 5 is inscribed in a equilateral triangle. What is the area of the triangle's area minus the circle's a

Aleonysh [2.5K]

First off, the area of the circle would be 78.54

Now, you would do (area of the triangle)--- AT-78.54=answer

I don't know how to find the area of the triangle with just the circle's radius, so this is all I can do. I'm sorry!

4 0

3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

2 sin x cos x – sin x = 0

solniwko [45]

Answer: PiN, Pi/3+2PiN, 5Pi/3+2PiN

Step-by-step explanation: Use formula sheet

7 0

3 years ago

n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

$A = Pe^{rt}$

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

$A=2400 e^{0.0168\times 20}$

$=2400 e^{0.336}$

$= 3358.4136$

$\approx 3358$

6 0

3 years ago