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Mademuasel [1]
3 years ago
8

On the three quizzes so far, Eric has scored 75, 92, and 83. What must he score on the fourth

Mathematics
1 answer:
AVprozaik [17]3 years ago
3 0
He can make a 70 or higher to keep a B avg.
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Can someone pls help
galben [10]

Answer:

1st - c

2nd - d

Step-by-step explanation:

jere is your answer

8 0
3 years ago
A cart weighing 200 pounds rests on an incline at an angle of 40 degrees. what is the required force to keep the cart at rest? r
MAXImum [283]

The force needed to keep the cart at rest is 149.022 pounds

<h3>Force and Motion</h3>

Given Data

  • Weight of cart = 200 pounds
  • Angle = 40 degree

The force needed to keep the cart at rest is the vertical component of the resultant force, hence we have

Fy = Mg sin θ

Substituting our given data we have

Fy = 200 sin 40

Fy = 200 *0.74511

Fy = 149.022 pounds

Learn more about force here:

brainly.com/question/12970081

7 0
3 years ago
What are the solutions to the quadratic equation (5y + 6)2 = 24? y = StartFraction negative 6 + 2 StartRoot 6 EndRoot Over 5 End
Paladinen [302]

Answer:

there are two solutions:

a) y=\frac{-6+2\sqrt{6} }{5}, and

b) y=\frac{-6-2\sqrt{6} }{5}

Step-by-step explanation:

In the equation: (5y+6)^2=24, since a perfect square with the unknown "y" is isolated on the left of the equal sign, we start by applying the square root on both sides of the equality, and then on isolating the unknown:

(5y+6)^2=24\\\sqrt{(5y+6)^2} =+/-\sqrt{24} \\(5y+6)=+/-\sqrt{6*4} \\(5y+6)=+/-2\sqrt{6}\\5y=-6+/-2\sqrt{6}\\y=\frac{-6+/-2\sqrt{6} }{5}

Therefore there are two solutions:

a) y=\frac{-6+2\sqrt{6} }{5}, and

b) y=\frac{-6-2\sqrt{6} }{5}

10 0
3 years ago
Read 2 more answers
Solve for n.<br>3/4n = 1 3/4n - 18
Alexus [3.1K]

3/4n=1 3/4n-18

3/4n=7/4n-18

3/4n-7/4n=7/4n-18-7/4n

-n=-18

-n/-1=-18/-1

<u><em>N=18</em></u>

5 0
4 years ago
Any help is greatly appreciated but please show how to get answers
seraphim [82]

We first calculate the front and back which are 2 congruent(equal) triangles. The 2 areas together is...

9*6/2*2=54

Now we want to calculate the 2 rectangles at the top right and top left of the shape they are also congruent(equal). The 2 areas together is...

7*5*2=70

The last part is the rectangle on the bottom with area...

9*5=45

Now we just need to add them all together...

54+70+45=124+45=169

I hope this helped you, if you have any questions about this solution just ask me in the comments :)

8 0
3 years ago
Read 2 more answers
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