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natka813 [3]
4 years ago
8

What is the least common multiple of 5 and 150

Mathematics
2 answers:
seropon [69]4 years ago
3 0

the answer is 150. 150 is the least common multiple of 150, and 150 is a multiple of 5.

Jet001 [13]4 years ago
3 0

<u><em>Answer: The least common multiple of 5 and 150 is 150.</em></u>

Step-by-step explanation:

You had to find the prime factorization of 5.

5=5

Then you had to find the prime factorization of 150.

2*3*5*5=150

150 is the least common multiple.

Hope this helps!

Thanks!

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Please simplify the following distributive property expression:
guapka [62]

You are correct


4(3x-5)

4(3x) + 4(-5)

12x-20

6 0
3 years ago
Can someone help me please!!
ratelena [41]

The coordinates of E are (5.75, 0).

<h3>What is midpoint?</h3>

The midpoint is the middle point of a line segment. It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.

Given that, C is the midpoint of AB, D is the midpoint of CB and E is the midpoint of DB.

Formula for coordinates of midpoint,

(x, y) = [(x1+x2)/2, (y1+y2)/2]

Coordinates of C;

(x, y) = (-10+8)/2, (14-2)/2

(x, y) = (-1, 6)

Coordinates of D;

(x, y) = (-1+8)/2, (6-2)/2

(x, y) = (3.5, 2)

Coordinates of E;

(x, y) = (3.5+8)/2, (2-2)/2

(x, y) =  (5.75, 0)

Hence, The coordinates of E are (5.75, 0).

For more references on midpoints, click;

brainly.com/question/28224145

#SPJ1

8 0
1 year ago
Melissa has more than 40 coins in her collection which inequality the nuber of coinsin melissas collection
nata0808 [166]

Answer:

X > 40

Step-by-step explanation:

Given that:

Let number of coins in her collection is more Than 40

To represent the number of coins in Melissa's collection as an inequality :

Let total number of items in her collection = X

Coins in her collection > 40

Hence, coins in her collection can be represented as :

X > 40

4 0
3 years ago
Knitting: You are knitting a blanket. You want the area of the blanket to be 24ft^2. You want the length of the blanket to be 2
andriy [413]
You can use factors to solve.  Determine all the factor pairs of 24, find the two that are two numbers apart.
1, 24 X
2, 12 X
3, 8 X
4, 6 YES!


Algebraic way to solve using Quadratics:
l = 2 + w

A = lw

A = (2 + w)w  Substitute (2 + w) for l

24 = (2 + w)w  Substitute 24 in for the area

24 = 2w + w^2  Distribute

w^2 + 2w - 24 = 0  Set equal to 0 (put in standard form)

(w + 6) (w - 4) = 0  Factor

w + 6 = 0  and w - 4 = 0    Set each factor equal to 0.

So w= -6 or w = 4 ... -6 makes no sense for a length!  So the width must be 4 and the length will be 4 + 2, which is 6.

5 0
4 years ago
In calculating the present value of $1,000 to be received 5 years from today, the discount factor has been calculated to be .700
Trava [24]
To calculate the present value we shall proceed as follows:
from the present value table, the percentage corresponding to discount factor of 0.7008 in 5 years is 7%
therefore using the formula:
FV=PV(1+r/100)^n
where:
FV=$1000
PV=?
r=7%

hence:
1000=PV(1+7/100)^5
PV=1000/(1+7/100)^5
PV=712.986

6 0
3 years ago
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