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2 years ago

Area= Help me please!! Thanks :)

Mathematics

1 answer:

Savatey [412]2 years ago

8 0

Answer:

80π

Step-by-step explanation:

Circle O with radius IO:

large radius = IO = 12 = R

Circle O with diameter JK

IJ = JK = KL = 2 × IO = 24

IJ = JK = KL = 24/3 = 8

small radius = 8/2 = 4 = r

The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.

That is the same as

1 semicircle of radius 12 plus 1 semicircle of radius 4

A = πR²/2 + πr²/2

A = π(12² + 4²)/2

A = 160π/2

A = 80π

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user100 [1]

Answer:

the diameter is: 14

the circumference is: C≈43.98

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Step-by-step explanation:

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3 years ago

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How did you identify the line of sight, angle of elevation and angle of depression?

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Answer:

The term angle of elevation denotes the angle from the horizontal upward to an object. An observer's line of sight would be above the horizontal. The term angle of depression denotes the angle from the horizontal downward to an object. An observer's line of sight would be below the horizontal.

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1 year ago

an Carlos County Health Department reported 17 new cases of tuberculosis in the first half of 2001 and 18 additional cases durin

Tpy6a [65]

Answer:

San Carlos County

Step-by-step explanation:

a) Data and Calculations:

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Number of cases of tuberculosis reported in the second half = 18

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Therefore, the incidence rate of tuberculosis in the county = 35/209,750 * 100

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5 0

3 years ago

CAN I PLEASE HAVE SOME HELP

sp2606 [1]

Answer:

I am pretty sure it's A and I am very sorry if I'm wrong

Step-by-step explanation:

The way I would think about this question is this: because Jordan only wants to work a maximum of 40 hours, he can work 40 hours or less. Which is described as an equation in the top equation of letter A. And because he also wants to make $250 or more, the bottom equation in A would work as well.

I hope that makes sense! Please ask me in the comments if you want more explanation on it

7 0

3 years ago

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),

pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

$\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}$

$(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}$

When t=0, S(t)=15

$15=30+Ce^{-k*0}\\C=15-30\\C=-15$

When t = 2, S(t)=20

$20=30-15e^{-2k}\\20-30=-15e^{-2k}\\-10=-15e^{-2k}\\e^{-2k}=\dfrac23\\$Take the natural log of both sides$\\-2k=\ln \dfrac23\\k=-\dfrac{\ln(2/3)}{2}$

Therefore:

$S(t)=30-15e^{\frac{\ln(2/3)}{2}t}\\$When t=3$\\S(t)=30-15e^{\frac{\ln(2/3)}{2} \times 3}\\S(3)=21.8 \approx 22$

8 0

3 years ago