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3 years ago

List the perfect squares between 100 and 500 that are even numbers.

1 answer:

7 0

The perfect squares between 100 and 500 are:

100 (10²)

121 (11²)

144 (12²)

169 (13²)

196 (14²)

225 (15²)

256 (16²)

289 (17²)

324 (18²)

361 (19²)

400 (20²)

441 (21²)

and

484 (22²) .

The squares of odd numbers are odd.
The squares of even numbers are even.

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Determine the value of x in the figure

goblinko [34]

I think it’s B x = 137

4 0

2 years ago

Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

Choose the first alternative

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

Probabilities

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

2 years ago

Read 2 more answers

Subtract 1/6a+3 from 1/3a−5 PLZ HELP ASAP

lukranit [14]

Answer:

1/3a - 5 - (1/6a + 3) =

1/3a - 5 - 1/6a - 3 =

1/3a - 1/6a - 5 - 3 =

2/6a - 1/6a - 8 =

1/6a - 8 <===

Step-by-step explanation:

5 0

3 years ago

Helppppp plzzzz ASAP!!!!!! Thank you!!!!!!

Zielflug [23.3K]

Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values of p from s

PS = (4 - 2 , 2 - 4)

PS = (2 , -2)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

PS = √ 4 + 4

PS = √8

PS = 2√2

S = (4 , 2)

R = (8 , 6)

SR = (8-4 , 6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

SR^2 = 4^2 + 4^2

SR = √ (16 + 16)

SR = √32

SR = 4√2

having the values of 2 of its sides we multiply them and obtain their area

PS * RS = Area

2√2 * 4√2 =

3 0

3 years ago

14w – 2(1 – w) = 2(5w - 1)

joja [24]

Answer:

w = 10

Step-by-step explanation:

Solving steps are shown in above pic. (source: Photomath)

8 0

3 years ago