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ivann1987 [24]
3 years ago
15

Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

x = -1/3

Step-by-step explanation:

x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)

= -6/18 = -1/3

x-(-1/3) = 0 ---> x = -1/3

aivan3 [116]3 years ago
5 0

Answer:

x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}

Step-by-step explanation:

For this function [f(x)=9x²+6x+1], we'll solve it by the traditional way, via General Formula

9x^{2}+6x+1=0 \Rightarrow x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}\Rightarrow x=-\frac{1}{3}\Rightarrow S=\left \{ -\frac{1}{3} \right \}

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