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ivann1987 [24]
3 years ago
15

Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

x = -1/3

Step-by-step explanation:

x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)

= -6/18 = -1/3

x-(-1/3) = 0 ---> x = -1/3

aivan3 [116]3 years ago
5 0

Answer:

x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}

Step-by-step explanation:

For this function [f(x)=9x²+6x+1], we'll solve it by the traditional way, via General Formula

9x^{2}+6x+1=0 \Rightarrow x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}\Rightarrow x=-\frac{1}{3}\Rightarrow S=\left \{ -\frac{1}{3} \right \}

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What is the measure of angle x? Show or explain how you know.
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Answer:

65 degrees

Step-by-step explanation:

y is a right angle and a is 30 degrees. this means that the supplementary engle of x is 45 plus 70 which is 115. 180-115 = 65 degrees.

8 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
Write an equation for the description. the sum of 17 and a number x is equal to 21
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Answer:

Equation: 17+x=21

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7 0
3 years ago
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netineya [11]

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3 years ago
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Identity the construction that the figure represents
nordsb [41]

The construction is the construction of the Perpendicular bisector.

<h3>How to illustrate the information?</h3>

The steps for the construction of perpendicular bisectors are as follows:

Open the compass more than half of the distance between A and B, and scribe arcs of the same radius centered at A and B.

Call the two points where these two arcs meet X and Y. Draw the line between X and Y.

So, the point where this line meets the line segment; M is called the mid point and the line XY is the perpendicular bisector of the line AB.

The figure is a construction of perpendicular bisector.

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4 0
2 years ago
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