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2 years ago

Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.

Mathematics

2 answers:

CaHeK987 [17]2 years ago

6 0

Answer:

x = -1/3

Step-by-step explanation:

x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)

= -6/18 = -1/3

x-(-1/3) = 0 ---> x = -1/3

aivan3 [116]2 years ago

5 0

Answer:

$x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}$

Step-by-step explanation:

For this function [f(x)=9x²+6x+1], we'll solve it by the traditional way, via General Formula

$9x^{2}+6x+1=0 \Rightarrow x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}\Rightarrow x=-\frac{1}{3}\Rightarrow S=\left \{ -\frac{1}{3} \right \}$

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Solve for k.<br> 5(k+4)<–5

Amiraneli [1.4K]

Answer:

k < -5

Step-by-step explanation:

5(k+4)<–5

Divide each side by 5

5/5(k+4)<–5/5

k+4 < -1

Subtract 4 from each side

k+4-4 < -1-4

k < -5

5 0

3 years ago

A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9

geniusboy [140]

Answer:

$7.7$ km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of $6.6$ km and $3.9$ km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, $a^{2}+b^{2} =c^{2}$ , where $a$ and $b$ are the lengths of the triangle's legs and $c$ is the length of the triangle's hypotenuse. In this case, we know what $a$ and $b$ are, and we need to solve for c, so after substituting the given values of $a$ and $b$ into $a^{2}+b^{2} =c^{2}$ to solve for c, we get:

$a^{2}+b^{2} =c^{2}$

$6.6^{2} +3.9^{2} =c^{2}$ (Substitute $a=6.6$ and $b=3.9$ into the equation)

$43.56+15.21=c^{2}$ (Evaluate the squares on the LHS)

$58.77=c^{2}$ (Simplify the LHS)

$c^{2}=58.77$ (Symmetric Property of Equality)

$\sqrt{c^{2} } =\sqrt{58.77}$ (Take the square root of both sides of the equation)

$c=7.7,c=-7.7$ (Simplify)

$c=-7.7$ is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately $7.7$ km away from its base. Hope this helps!

7 0

3 years ago

Please help me with this

larisa [96]

Please Show a picture or either a text so that I can help you

7 0

3 years ago

Read 2 more answers

There are 500 rabbits in Lancaster on February 1st. If the amount of rabbits triples every month. Write a function that represen

Anuta_ua [19.1K]

Answer:

10,93,500.

Step-by-step explanation:

On first February total number of rabbits were 500.

Now it is given that after each month rabbit population will become triple of initial.

So, after one month rabbits will become 3×500.

After two months they will become $3^{2}$ ×500.

Thus , after m months total number of rabbits will become $3^{m}$ ×500.

Now,

On August 1 , 7 months will get passed from February 1 so putting m = 7 in the equation we get ,

Total number of rabbits = $3^{7}$ ×500 = 10,93,500.

8 0

3 years ago

Write your question here (Keep it simple and clear to get the best answer)what number is 20times table

kykrilka [37]

20×1=20
20×2=40
20×3=60
20×4=80
20×5=100
20×6=120
20×7=140
20×8=160
20×9=180
20×10=200
(Only include this if the table is up to 12)
20×11=220
20×12=240

6 0

3 years ago