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lbvjy [14]
3 years ago
9

Find the measure of angle c of a triangle ABC, if m

Mathematics
1 answer:
leonid [27]3 years ago
4 0
Bro show a picture I’ll help everyone out a lot
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Write a real world situation that can be represented by the expression x - 12 subtraction
Tju [1.3M]
Ed has $37 and decides that he wants to go out to lunch with his friend Barb. They go out to eat, and when it comes time to pay the bill they decide to split it. It will cost Ed $12 to pay his half. How much money will he have left after he pays his share?
3 0
3 years ago
A 9 cm tall cone shaped paper cup can hold up to 58.9 cm cubed of water. What is the minimum amount of paper needed to make the
babymother [125]
Volume of a cone, V = πr^2h/3

r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum

Surface area, A = πr [r+ Sqrt (h^2+r^2)] =  3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2

Therefore, minimum amount of paper required is 92.95 cm^2
4 0
3 years ago
How do you graph y=12/x
Tpy6a [65]

Answer: \frac{12}{x} is an asymptote

Step-by-step explanation:

Apply a table, and plug in values of x into the equation.  For example f(2)=\frac{12}{2} =6. That's one of the points on the graph that we just found (2,6)

7 0
2 years ago
HELP WITH THESE QUESTIONS PART 2.
polet [3.4K]

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

**********************************************************

Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

6 0
4 years ago
GI bisects DGH so that m DGI is x-3 and mIGH is 2x-13 find the value of x
baherus [9]

x = 10

since GI bisects ∠DGH then ∠DGI = ∠IGH, hence

2x - 13 = x - 3 ( subtract x from both sides )

x - 13 = - 3 ( add 13 to both sides )

x = 10



8 0
3 years ago
Read 2 more answers
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