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alexgriva [62]
3 years ago
14

How many moles of N2O3 contain 2.55x10^24 oxygen atoms?

Chemistry
2 answers:
makkiz [27]3 years ago
7 0

Answer : The number of moles of N_2O_3 is 1.41 moles.

Explanation :

In N_2O_3, there are 2 nitrogen atoms and 3 oxygen atoms.

As we know that, 1 mole of substance contains 6.022\times 10^{23} number of atoms.

As, 3\times 6.022\times 10^{23} number of oxygen atoms contains 1 mole of N_2O_3

So, 2.55\times 10^{24} number of oxygen atoms contains \frac{2.55\times 10^{24}}{3\times 6.022\times 10^{23}}=1.41 mole of N_2O_3

Therefore, the number of moles of N_2O_3 is 1.41 moles.

Musya8 [376]3 years ago
5 0
Moles of O = atom / avogadro's number = 2.55*10^24 / 6.022*10^23 = 4.23 mol 

<span>since each N2O3 contains 3 O atoms: </span>
<span>moles of N2O3 = moles of O / 3 = 1.41 mol

I searched on google sorry!</span>
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