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HACTEHA [7]
3 years ago
8

An atom of which element has the strongest attraction for electrons in a chemical bond?

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

Fluorine

Explanation:

Fluorine has the greatest attraction for electrons in any bond that it forms. The attraction of an atom for shared electrons is called its electronegativity.

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Look at the picture of two different substances above. Which substance is a mixture? A. Y and Z
Feliz [49]

Answer:

option B is correct.

Y is a mixture in the picture.

Explanation:

Different types of substances combine physically and form a mixture.  

Mixture formed by the combination of two or more substances that that combine in same physical state.

For example mixture of copper sulphate and solid chloride in dry form and that will look like white and blue crystal in a mixture.

The picture Z showing dots of same color and is not a mixture, while picture Y shows dots of different colors clearly indicating that it is picture for mixture.

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Which of these factors should remain constant in a simulation of natural
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A is your answer The ratio of females to males
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Which atoms in the pair has the larger atomic radius ? Help please !!
Ne4ueva [31]

A

1. Potassium, K.

2. Calcium, Ca.

3. Gallium, Ga.

4. Carbon, C.

5. Bromine, Br.

6. Barium, Ba.

7. Silicon, Si.

Explanation:

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3 years ago
Q2.  0.254 g of KHP (204 g/mol) titrated against 20.0 mL of unknown NaOH (40.0 g/mol) solution to get the end point of phenolpht
Vera_Pavlovna [14]

Answer:

<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>

Explanation:

No. of moles = \frac{mass}{molar mass}

= \frac{0.254}{204} = 0.001245 moles

Concentration of KHP (C1) in litres = n/v

= \frac{0.001245}{0.02} = 0.062 mol/L

We know that:

C_{1} V_{1} = C_{2} V_{2}

where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.

Since mole ratio is 1 : 1.

1 mole of NaOH - 40g

0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g

⇒0.0498g of NaOH was used during the titration

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<u><em>= 2.49g/L.</em></u>

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