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3 years ago

An atom of which element has the strongest attraction for electrons in a chemical bond?

Chemistry

1 answer:

lina2011 [118]3 years ago

4 0

Answer:

Fluorine

Explanation:

Fluorine has the greatest attraction for electrons in any bond that it forms. The attraction of an atom for shared electrons is called its electronegativity.

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a. silicon b. carbon c. beryllium d.chromium

zepelin [54]

The answer is silicon because it’s atomic number is 14

3 0

3 years ago

Read 2 more answers

A 250 ml solution of 2.0 M NaOH is diluted to 1.0 liter. What is the final concentration of the solution?

Alex73 [517]

Answer:

Diluted concentration is 0.5M

Explanation:

Let's solve this with rules of three, although there is a formula to see it easier

In 1000 mL (1L), we have 2 moles of NaOH

In 250 mL we must have (250 . 2) / 1000 = 0.5 moles of NaOH

These moles will be also in 1 L of the final volume of the diluted solution

More easy:

1 L of solution has 0.5 moles of NaOH

Then, molarity is 0.5 M

The formula is: Concentrated M . Conc. volume = Diluted M . Diluted volume

2 M . 0.250L = 1L . Diluted M

0.5M = Diluted M

3 0

3 years ago

Read 2 more answers

Select the correct answer.

frozen [14]

Answer:

1.79x10^-14

Explanation:

pOH + pH = 14

H+=10^-pH

- Hope that helps! Please let me know if you need further explanation.

3 0

3 years ago

How many grams of HF are needed to react with 3.0 moles of Sn?

Flauer [41]

Answer:

120g

Explanation:

Step 1:

We'll begin by writing the balanced equation for the reaction.

Sn + 2HF —> SnF2 + H2

Step 2:

Determination of the number of mole HF needed to react with 3 moles of Sn.

From the balanced equation above,

1 mole of Sn and reacted with 2 moles of HF.

Therefore, 3 moles Sn will react with = 3 x 2 = 6 moles of HF.

Step 3:

Conversion of 6 moles of HF to grams.

Number of mole HF = 6 moles

Molar Mass of HF = 1 + 19 = 20g/mol

Mass of HF =..?

Mass = number of mole x molar Mass

Mass of HF = 6 x 20

Mass of HF = 120g

Therefore, 120g of HF is needed to react with 3 moles of Sn.

3 0

3 years ago

1. Unas de las formas de producir nitrógeno gaseoso (N2) es mediante la oxidación de metilamina (CH3NH2), tal como se muestra en

Maslowich

Answer:

a) 4CH₃NH₂ + 9O₂ ⇄ 4CO₂ + 10H₂O + 2N₂

b) m = 5,043 g

c) % = 69,4 %

Explanation:

a) La ecuación balanceada es la siguiente:

4CH₃NH₂ + 9O₂ ⇄ 4CO₂ + 10H₂O + 2N₂

En el balanceo, se tiene en la relación estequiométrica que 4 moles de metilamina reacciona con 9 moles de oxígeno para producir 4 moles de dióxido de carbono, 10 moles de agua y 2 moles de nitrógeno.

b) Para determinar la masa de nitrógeno se debe calcular primero el reactivo limitante:

$n_{O_{2}} = \frac{m}{M} = \frac{25,6 g}{31,99 g/mol} = 0,800 moles$

$n_{CH_{3}NH_{2}} = \frac{4}{9}*0,800 moles = 0,356 moles$

De la ecuación anterior se tiene que la cantidad de moles de metilamina necesaria para reaccionar con 0,800 moles de oxígeno es 0,356 moles, y la cantidad de moles iniciales de metilamina es 0,5 moles, por lo tanto el reactivo limitante es el oxígeno.

Ahora, podemos calcular la masa de nitrógeno producida:

$n_{N_{2}} = \frac{2}{9}*n_{O_{2}} = \frac{2}{9}*0,8 moles = 0,18 moles$