Answer:
The correct answers are "After adding the 0 test score, the mean would be affected.", ad "Before the missed test, Eva’s median score was 91".
Step-by-step explanation:
We know that the mean and median scores would not be helpful in determining Eva's abilities since the 0 is not a representation of how much she knows. However, it will affect the average as adding a 0 to the numerator and a 1 to the denominator will lower the average.
Finally, we can tell the median is 91 before added as when we line up the scores in ascending order, the middle number is 91.
82, 90, 91, 96, 100
Answer:
Option B) minimum value at −10
Step-by-step explanation:
we have
This function represent a vertical parabola open upward (because the leading coefficient is positive)
The vertex represent a minimum
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Divide the coefficient of term x by 2
10/2=5
squared the term and add to the right side of equation
Remember to balance the equation by adding the same constants to the other side
rewrite as perfect squares
----> function in vertex form
The vertex of the quadratic function is the point (5,-10)
therefore
The minimum value of the function is -10
9.10
+2.53
————
11.63
Just add the rows from the top to the bottom
Answer:
6a. r^5
6b. 18(4+√2)
Step-by-step explanation:
6a. The first term of the sequence is √r, and the common ratio is √r. Hence the 10th term will be ...
a1·r^(n-1) . . . for a1=√r and n=10.
√r·(√r)^(10-1) = (√r)^10 = r^5
_____
6b. The sum of n terms is given by ...
Sn = a1·(R^n -1)/(R -1)
For a1=√8 and the common ratio R = √8, the sum of 4 terms is ...
Or, you could add up the 4 terms: