The answer is 8.33333333333333333...
I think it’s QT EJ and HA
2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10
See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48
<h3>How to graph the inequalities?</h3>
The inequalities are given as:
x + 7y ≤ 49
6x + y ≤ 48
The domain and the range are:
x ≥ 0
y ≥ 0
This means that, we plot the inequalities x + 7y ≤ 49 and 6x + y ≤ 48 under the domain and the range x ≥ 0 and y ≥ 0
See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48
Read more about inequalities at:
brainly.com/question/25275758
#SPJ1
Answer:
The correct answer is:
y= x-8
Step-by-step explanation:
We have the equation: 8 = x-y
By clearing the equation for y (subtracting x both sides of equation) we have:
8 - x = -y (1)
Multiplying (1) by -1
-8+x = y (2)
Re-arranging (2), finally we have:
y= x-8