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2 years ago

How much greater is 300 than 3

Mathematics

2 answers:

m_a_m_a [10]2 years ago

6 0

300-3=297. Hope this helps!

lana66690 [7]2 years ago

4 0

300/3 = 100
so 300 is 100 times greater then 3

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I can't find the answer

Rudik [331]

Answer: what grade is this

Step-by-step explanation:

3 0

2 years ago

If you could answer all of these that would be very helpful please help!!

Vlad [161]

0.75 is equal to 6\8
5.8 is > 4\5
a decimal greater than 5\8 is 1.2
0.2 > 1\4
0.7>0.6
a decimal smaller than 6\8 is 0.01
The one that is not equal to -7\5 is -11\5
The answer is D

3 0

2 years ago

miss. Nikkel want to divide her class of 23 students into 4 equal teams.is this reasonable?why or why not

ella [17]

No, because if you divide 23 / 4, you get 5.75. You can't get 0.75th of a kid. So it is not reasonable, because it is a decimal, and not a whole number.

Hope this helped! ☺♥

6 0

3 years ago

Read 2 more answers

A country will produce 3000 missiles this year. Each of the short-range missiles cost $200000 to produce. Each of the medium-ran

Lynna [10]

Answer:

$350,000

Step-by-step explanation:

Let's define:

s: amount of short-range missiles produced

m: amount of medium-range missiles produced

l: amount of long-range missiles produced

From the total production and the ratios we can write the following equations:

s + m + l = 3000

s/m = 3/3 = 1 = m/s

s/l = 3/4 or l/s = 4/3

Dividing the first equation by s, we get:

s/s + m/s + l/s = 3000/s

1 + 1 + 4/3 = 3000/s

10/3 = 3000/s

s = 3000*3/10 = 900

m = 900

l = 4/3*900 = 1200

From the money that the countries plans to use and each missile cost, we can write the following equation:

200,000*s + 300,000*m + cost*l = 870,000,000

Replacing with previous result:

200,000*900 + 300,000*900 + cost*1200 = 870,000,000

cost = (870,000,000 - 200,000*900 - 300,000*900)/1200 = 350,000

3 0

2 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

2 years ago