Answer:
x = 5.5
EF = 14
Step-by-step explanation:
We can use ratios to solve
AG 7
----------- = -----------------
EG 2x+3
We know that EG is 2 times AG since A is the midpoint
AG 7
----------- = -----------------
2 AG 2x+3
Canceling like terms
1 7
----------- = -----------------
2 2x+3
Using cross products
1 (2x+3) = 2*7
2x+3 = 14
Subtract 3 from each side
2x+3-3 = 14-3
2x =11
Divide by 2
x = 11/2
x = 5.5
EF = 2x+3 = 2*5.5+3 = 14
Answer:
Given that JK = MN, JK = KL, and LM = MN, therefore, by transitive property, we have;
KL ≅ LM
Step-by-step explanation:
The given information are;
The midpoint of the segment JL = The point K
The midpoint of the segment LN = The point M
Given that JK = MN
The two column proof is given as follows;
Statement Reason
1) JK = KL Definition of the midpoint of segment JL
2) LM = MN Definition of the midpoint of a segment LN
3) JK = MN Given
4) KL ≅ LM Transitive property.
The answer is b. It would turn into y=7x+13