2 + 2 = 4 because 4 is a sum of 1-digit numbers
2 + 2 ≠ 22 because 22 is the sum of 1-digit and 2-digit numbers
Step-by-step explanation:
Lets explain some important notes:
- The 1-digit number consists of one digit, 4 is a one-digit number
- The 2-digit number consists of two digits, ones digit and tens digit, 23 is a 2-digit number, the ones digit is 3 and the tens digit is 2, so its value is 20 + 3
- The 3-digit number consists of ones digit, tens digit and the hundreds digit, 123 is a 3-digit number, the ones digit is 3, the tens digit is 2 and the hundreds digit is 1, so its value is 100 + 20 + 3
∵ 2 + 2 is the addition problem of two 1-digit numbers
∴ There sum will be 4 which is also 1-digit number
∴ 2 + 2 must be 4
∵ 22 is a two digit number
∴ Its value is 20 + 2 ⇒ not 2 + 2
∴ 2 + 2 can not be 22
2 + 2 = 4 because 4 is a sum of 1-digit numbers
2 + 2 ≠ 22 because 22 is the sum of 1-digit and 2-digit numbers
Learn more:
You can learn more about the place value of numbers in brainly.com/question/13174282
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Answer: 14.967
Step-by-step explanation:
Use Pythagorean Theorem to find the missing length.
a² + b² = c²
x² + 10² = 18²
x² + 100 = 324 [Subtract 100 from both side]
x²= 224
√x² = √224 [solve the square root from both sides]
x ≈ 14.967
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
Volume of cylinders = pi x r^2 x height Simplifying the ratio: 1.6/3 = 16 / 30 (multiply and divide by 10 to remove the decimal) Volume Ratio = 512:27
