Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
Answer:
positive slope
(0,3)
slope = 2
Step-by-step explanation:
- Slope of the given line is positive
- If the line is sloping upward from left to right, so the slope is positive (+).
or if the angle made by the line to the x axis is < 90 it's slope is positive.
- y-intercept of the line is (0,3)
- The y intercept is the point where the line crosses the y axis. At this point x = 0.
- slope of the line is 2
- slope = (y2 - y1) / (x2 - x1)
lines passing through points (1,5) (0,3)
slope = (3 - 5) / (0 - 1)
= -2 / -1 = 2
.75 75% 3/4 is the correct answer
Since one package cost $24 and each person puts $6 .you then divide 24 divided by 6 then you get four people
For 10, the slope is 1/2 and the y intercept is 0. For 12 i believe its 4 for both the slope and the y intercept.
