Ask question

Ask question

All categories

3 years ago

13

Evaluate the integral. ∫50∫25−x2√−25−x2√∫25−x2−z2√−25−x2−z2√1(x2+y2+z2)1/2dydzdx∫05∫−25−x225−x2∫−25−x2−z225−x2−z21(x2+y2+z2)1/2d

ydzdx

1 answer:

Kipish [7]3 years ago

4 0

Is that a valid question?

You might be interested in

Find the median of 19, 29, 36, 15, and 20. Show all the steps that you took to find your answer.

inessss [21]

Answer:

15,19,20,29,36

N=5

Median =n+1/2

=6/2

=3

Terfore 3rd absorbation is meadian

:. 20 is the answer

5 0

2 years ago

Identify the constant of<br> proportionality (k)<br> 8Y = 16x<br> k=

RUDIKE [14]

Answer:

JUST WRITE THIS AS YOUR ANSWER

Step-by-step explanation:

Step 1: Put together the general equation.

Step 2: Solve for the constant of proportionality.

Step 3: Plugging the constant into the equation, solve for the unknown variable.

Let's solve a few problems to see how this works, shall we?

Example 1: Y is directly proportional to x. When x = 5, y = 8. What does y equal when x = 9?

First, we set up our general equation. Because y is directly proportional to x, we have:

y = cx

where c is the constant of proportionality. In other words, when x goes up, y goes up, and when x goes down, y goes down.

The next thing we do is plug our values for x and y into the equation so we can solve for c:

8 = (c)(5)

Solving for c, we get c = 8/5 = 1.6 and we plug this into our equation:

y = 1.6x

Now, we can plug x = 9 into the equation to find out what y equals:

y = (1.6)(9)

y = 14.4

So, our answer is 14.4

Example 2: Y is directly proportional to the square of x. When x = 2, y = 32. What does y equal when x = 5?

This time, our general equation is slightly more complicated because x is squared:

y = cx2

Like before, we solve for our constant:

32 = (c)(22)

32 = (c)(4)

We get c = 8:

y = 8x2

Solving for y when x = 5, we get y = (8)(52) = (8)(25) = 200

Example 3: Y is inversely proportional to x. When x = 2, y = 8. What does y equal when x = 24?

This time, because y is inversely proportional to x, our general equation is different:

xy = c

so when x goes up, y goes down, and vise versa. But, other than that, we solve these kinds of problems the same way as direct proportion problems. Solving for the constant, we get:

(2)(8) = c

So c = 16 and our equation is now:

xy = 16

Solving for y when x = 24 we get y = 16/24 = 2/3

Example 4: Y is inversely proportional to the square root of x. When x = 36, y = 2. What does y equal when x = 64?

As before, we set up our equation:

eq001

Since the square root of 36 is 6, it is easy to solve for c:

(6)(2) = c

We get c = 12 and our equation is now:

eq002

Solving for y when x = 64 we get 8y = 12 or y = 12/8 = 1.5 because the square root of 64 is 8.

6 0

3 years ago

What's the answer for 3/4 (x+3)=9

Vitek1552 [10]

We want to solve the equation :

$\displaystyle{ \frac{3}{4}(x+3)=9$

first, multiply both sides by 4:

$\displaystyle{ \cancel{4} \cdot \frac{3}{ \cancel 4 }(x+3)=4\cdot 9$

$\displaystyle{ 3(x+3)=36$

divide both sides by 3:

$x+3=12$

add -3 to both sides:

$x=9$

Answer: x=9

3 0

3 years ago

Need help for geometry.

polet [3.4K]

Answer: The first.

Step-by-step explanation: If you draw out a triangle and lable the points on each point with values from each triangle, you get J=M, K=N, and L=O. The first is the only one that proves it.

8 0

3 years ago

PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the

stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

3 0

3 years ago