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Over [174]
3 years ago
6

the scale of a model railroad set is 3.5 millimeters to one foot if the length of a model car in the set is 150 millimeters what

is the length of the car
Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0

the answer is 43 ft i just help my little brother with that question and he got it right

Montano1993 [528]3 years ago
6 0

\bf \begin{array}{ccll} \stackrel{mm}{model}&\stackrel{ft}{actual}\\ \cline{1-2} 3.5&1\\ 150&x \end{array}\implies \cfrac{3.5}{150}=\cfrac{1}{x}\implies x=\cfrac{150\cdot 1}{3.5}\implies x\approx 42.86

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Vroom Vacuums sells the Tornado vacuum cleaner. Each Tornado has a one-year warranty that covers any product defects. When custo
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Answer:

Performance obligation:

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8 0
3 years ago
Order the numbers from least to greatest: -7/8, 7/4, -15/2, and -13/16
VikaD [51]
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8 0
3 years ago
The first and third quartiles
aalyn [17]
1.  You'll need to download this data, or copy it down by hand.
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2 years ago
Which of the following is the measure of ZAXY if ray x bisects ZAXB,
weqwewe [10]

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6 0
2 years ago
Read 2 more answers
Help me find the volume of the composite figure
Butoxors [25]

Answer:

V = 97.911in^3

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

V_1 = l^3

Where

l = side length = 5.1

V_1 = 5.1^3

V_1 = 132.651

Next, calculate the volume of the cone using:

V_2 = \frac{\pi r^2h}{3}

Where

h = 5.1

r = \frac{1}{2} * Diameter

r = \frac{1}{2} * 5.1

r = 2.55

So, we have:

V_2 = \frac{\pi r^2h}{3}

V_2 = \frac{\pi * 2.55^2 * 5.1}{3}

V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}

V_2 = \frac{729.5805}{21}

V_2 = 34.74

The volume of the figure is:

V=V_1 - V_2

V_1 = 132.651

V = 132.651 - 34.74

V = 97.911in^3

8 0
2 years ago
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