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andriy [413]
3 years ago
11

True or False? If a radius of a circle intersects a chord, it is perpendicular to that chord.

Mathematics
2 answers:
evablogger [386]3 years ago
5 0

Answer:

False

Step-by-step explanation:

If a  radius of circle intersect a chord then it is not necessary that it bisect the chord.

If the radius bisects the chord then it will be perpendicular to chord.

But, if does not bisect the chord then it won't be perpendicular to that chord.

The radius is perpendicular to chord when it bisects that chord .

Hence, if a radius of a circle intersects a chord, it is not  perpendicular to that chord.

Answer : False

kifflom [539]3 years ago
4 0
If a radius of a circle intersects a chord, it would be unlikely for it to be perpendicular to that chord, so your answer choice for this question should be false.
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In the school library, there is 28 fiction items to every three non-fiction items. which is the best estimate of how many total
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there will be 537 items in the library

Step-by-step explanation:

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45,60
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Answer:

Step-by-step explanation:

I don't understand what the numbers before the language mean. I will answer the questions that have a definite language.

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What is this word  numharthotic

26 = 2 * 13

49 = 7 * 7

The smallest number that can be divided by both with no remainder is

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6 0
3 years ago
The sum of three numbers 13. The sum of twice the first number, five times the second number, and six times the third number is
Kruka [31]

Answer:

The three numbers are 56/5, -39/5 and 78/5.

Step-by-step explanation:

EQUATION 1:

First number: x

Second number: y

Third number: z

x + y + z = 19

EQUATION 2:

Sum of following is 77

Twice the first number: 2x

5 times the second number: 5y

6 times the third number: 6z

So, 2x + 5y + 6z = 77

EQUATION 3:

Difference between first and second number is 19.

x - y = 19

Equation 1: x + y + z = 19

Equation 2: 2x + 5y + 6z = 77

Equation 3: x - y = 19

1. Find x in terms of y

x - y = 19

x = 19 + y

2. Find y in terms of z by putting the value of x in first and second equation

  x + y + z = 19

  (19 + y)+ y + z = 19

  2y + z = 19 - 19

  2y + z = 0

  y = -z/2

and

2(19+y)+5y+6z=77

now putting the value of y in this equation

2(19-z/2)+5(-z/2)+6z=77

38 - z -5z/2 +6z = 77

5z/2 + 38 = 77

5z/2 = 39

z = 78/5

Now, y = -z/2

y = (-78/5)/2

y = -39/5

and  x = 19 + y

x = 19 - 39/5

x = 56/5

Therefore, the three numbers are 56/5, -39/5 and 78/5.

Keyword: Sum

Learn more about sum at

brainly.com/question/10666510

brainly.com/question/4034547

#LearnwithBrainly

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2 years ago
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That would be A

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y = 1/4 x

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