1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pogonyaev
1 year ago
10

According to the 2010 census data, the population of Texas was about 25,000,000 people. The land area of Texas is about 260,000

m^2. What was the average number of people per square mile in 2010?
Mathematics
2 answers:
Monica [59]1 year ago
8 0

Answer:249037470.178  peoples per mi^2

Vinil7 [7]1 year ago
5 0
It should be close to 1,000
You might be interested in
A culture started with 3000 bacteria. After 2 hours it grew to 3300 bacteria. Predict how many bacteria will be present after 16
bixtya [17]

Answer:

6,430\ bacteria

Step-by-step explanation:

we have a exponential function of the form

y=a(1+r)^{x}

where

y is the population of bacteria

a is the initial value

r is the rate of growth

x is the number of hours

we have

a=3,000 bacteria

y=3,000(1+r)^{x}

For x=2, y=3,300

substitute

3,300=3,000(1+r)^{2}

(3,300/3,000)=(1+r)^{2}

Apply square root both sides

1+r=\sqrt{3.3/3}

r=\sqrt{3.3/3}-1

r=0.0488

r=4.88\%

substitute in the equation

y=3,000(1+0.0488)^{x}

y=3,000(1.0488)^{x}

<u><em>Predict how many bacteria will be present after 16 hours</em></u>

For x=16 hours

substitute

y=3,000(1.0488)^{16}

y=6,430\ bacteria

6 0
3 years ago
Why do the probability of an event and the probability of its complement add up to 1
Ad libitum [116K]
<span>the probability of an event and the probability of its complement add up to 1 because the total events are the even it self and its compliment, so its probability equal to 1 because these are all the possible events that will occur. for example a coin toss, an event head will happen 0.5, and its complement is tails which will also happens 0.5</span>
5 0
3 years ago
Reasoning Graph the set of ordered pairs (0, 2). (1.4), (2,6). (3.8). Determine whether the relationship is a linear function Ex
polet [3.4K]

Answer:

No, it does not. See below.

Step-by-step explanation:

Lets find out the linear equation that passes trough (-2, 0) and (0, -6).

We know every linear equation has the form: y = mx + b

Where m is the slope on the curve and b the independent term.

We know that, given 2 points (x1,y1) and (x2,y2) we can find the slope m as:

m = (y2-y1)/(x2-x1)

In our case lets replace (x1,y1) and (x2,y2) by (-2, 0) and (0, -6) (notice it could be done in the inverse sense where (-2, 0) is (x2,y2) and (0, -6) is (x1,y1) ). So, our slope is:

m = [-6 - 0] / [0 - (-2)]

m = -6/2 = -3

So, we have a downward linear function with slope -3, this is:

y =  -3x + b

Now, for finding b just replace any of the 2 points given in the equation. Lets replace (-2, 0):

0 = -3(-2) + b

0 = 6 + b

Subtracting 6 in both sides:

-6 = b

So, our independent term is -6 and the function is:

y = -3x - 6

Now lets see if this linear eqution passes trough (2,6). If it does, we can replace the values on the equation. Replacing x by 2:

y = -3(2) - 6 = = -6 - 6 = - 12

So, in our equation, we x is 2 y is -12, and not 6 as in the point (2,6). So, our equation does not passes trough (2,6)

5 0
2 years ago
What is b^3+49b when factored
Over [174]
B(b^2+49)
There you go I found this on math papa.com
8 0
3 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
2 years ago
Other questions:
  • How is 5,067,000 written in standard scientific notation?
    5·1 answer
  • Suppose an automotive repair company wants to determine the current percentage of customers who keep up with regular vehicle mai
    7·2 answers
  • What is x is greater than or equal -6
    13·1 answer
  • Write 3,680,225 in expanded form​
    12·1 answer
  • Solve: 2(x-2)=6 please! also calculate the area of a circle with a diametre of 6 if the pie= 3
    15·1 answer
  • Solve K = 1/2 mv^2 for m
    15·1 answer
  • HELPPPPPPPPPPPPPP
    15·1 answer
  • A right triangle has an angle measure of 52.4 degrees. What is the value of 'x', the missing angle?
    13·1 answer
  • Can u help me on this pl
    12·1 answer
  • What are the dimensions of the poster at 1/2 it’s current size
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!