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algol [13]
3 years ago
5

Solve. show your work373 × 25​

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Step-by-step explanation:

let me show u 2 ways....

25 = 100/4 so,

373 × 25 = 373×100/4

=37300/4

=9,325

or u can use the normal way that I've attached..

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Math experts WHATS the Awnser to the equation
seropon [69]

Answer:

wow thats hard

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Alex wrote the expanded form for the number 165.038 as "100 60 5 30 8." was he correct? if not, give the correct expanded form.
grin007 [14]

The expanded form for the number 165.038 is 100+60+5+0.03+0.008.

<h3>What is the expended form of decimal numbers?</h3>

Writing decimals in expanded form simply means writing each number according to its place value. This is done by multiplying each digit by its place value and adding them together. Let's look at an example: 2.435. In words, we would say this as two and four hundred thirty-five thousandths.

In the given question expended form 100+60+5+30+8 is wrong.

After decimal point the first digit is at the tenth place and second digit at the hundredth place and third is at the thousandth place and so on....

165.038  = 100+60+5+\frac{0}{10}+\frac{3}{100}+\frac{8}{1000}            

              = 100+60+5+0.03+0.008

Hence, The correct expended form of the given number is 100+60+5+0.03+0.008.

To learn more about expended form from the given link:

brainly.com/question/603715

#SPJ4

5 0
2 years ago
15 points!! Please answer &lt;33
Mariulka [41]

Answer:

number 4

Step-by-step explanation:

let me know if i am worng and thank you

5 0
2 years ago
Read 2 more answers
Does anyone know how to solve this?
Bezzdna [24]

Use this version of the Law of Cosines to find side b:

b^2 = a^2 + c^2 − 2ac cos(B)

We want side b.

b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)

After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.

Try it....

6 0
3 years ago
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


4 0
3 years ago
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