His friend tub was 48 ounces and Francisco was .75 of 48. So, 48x 0.75 = 38.6
The values of x are 2 and -1.
Solving the equation created by substitution listed in the question:
-2x+14=x²-3x+12
Add 2x to both sides:
-2x+14+2x=x²-3x+12+2x
14=x²-1x+12
Subtract 14 from both sides:
14-14=x²-1x+12-14
0=x²-1x-2
Factoring this, we want factors of -2 that sum to -1; -2(1) = -2 and -2+1=-1:
0=(x-2)(x+1)
Using the zero product property, we know that either x-2=0 or x+1=0:
x-2=0
x-2+2=0+2
x=2
x+1=0
x+1-1=0-1
x=-1
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that

Putting
, we get



Therefore, the measure of angle RQP is 33 degrees.
Answer:
Step-by-step explanation:
1. 2x + y
2. 48 + 60 = 108
3. 840 - 210 = 630
Answer:
it could be x= 10 and y=7? I think bc 17 can be split up into 10 and 7 or 9 and 8 etc.