Two parallel lines are crossed by a transversal.
2 answers:
You might be interested in
Answer:
The value of x for equation is 3.4
The value of y for equation is 5.2
Step-by-step explanation:
Given as :
The two linear equation are
2 x + y = 12 ........A
4 x - 3 y = 2 .........B
Now, Solving both equations , we get
3 × ( 2 x + y ) + (4 x - 3 y) = 3 × 12 - 2
Or, 6 x + 3 y + 4 x - 3 y = 36 - 2
Or, (6 x + 4 x) + (3 y - 3 y) = 34
Or, 10 x + 0 = 34
∴ x =
i.e x = 3.4
So, The value of x for equation , x = 3.4
Put the value of x into eq A
∵ 2 x + y = 12
Or, y = 12 - 2 x
Or, y = 12 - 2 × 3.4
Or, y = 12 - 6.8
∴ y = 5.2
So, The value of y for equation , y = 5.2
Hence, The value of x for equation is 3.4 and The value of y for equation is 5.2 Answer
Answer:
Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.
Step-by-step explanation:
Given : In the figure attached, Length of girl EC = 4 ft
Length of street light AB = 25 ft
Girl is moving away from the light with a speed = 6 ft per sec.
To Find : Rate () of the tip (D) of the girl's shadow (BD) moving away from th
light.
Solution : Let the distance of the girl from the street light is = x feet
Length of the shadow CD is = y feet
Therefore, feet per sec. [Given]
In the figure attached, ΔAFE and ΔADE are similar.
By the property of similar triangles,
25x = 21(x + y)
25x = 21x + 21y
25x - 21x = 21y
4x = 21y
y =
Now we take the derivative on both the sides,
=
=
≈ 1.14 ft per sec.
Since w = x + y
Therefore,
= 7.14 ft per sec.
Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.
