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amm1812
4 years ago
10

Ken spends $2.50 for 3 pens. At this rate,what will he spend for 5 times as many pens?

Mathematics
1 answer:
kotykmax [81]4 years ago
8 0
You have to multiply 2.50 by 5 and the result is12.50
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Thomas invested $1498.00 at 6% simple interest per annum calculate How long it will be before his investment earns $449.40
valentinak56 [21]

Answer:

t = 6 years

Step-by-step explanation:

Use the simple interest formula:  i = prt, where p is the principal, r is the interest rate as a decimal fraction, and is the elapsed time, in years.

Here we want to know how long it will take for the interest alone to reach $449.40.  We first solve i = prt for t, obtaining t = i/(pr).

Here, the length of time is t = ($449.40) / (0.06*$1498.00).  This works out to

t = 5.9947, or approximately 6 years.

t = 6 years

8 0
3 years ago
What is the domain of the function
Svet_ta [14]

Answer:

The answer would be D, 0 < x < 4

Step-by-step explanation:

Because Domian is left to right of a function, so left to right would be 0 to 4

7 0
4 years ago
4. In this figure, B↔A↔
LenaWriter [7]

Answer:

B. 25 degrees

Step-by-step explanation:

i think

6 0
3 years ago
Can anyone help me out on this question?
svp [43]

Firstly , we will check continuity at x=1

we can use method

Suppose, f(x) is continuous at x=c

then it must satisfy

\lim_{x \to c} f(x)=f(c)

\lim_{x \to 1} f(x)=f(1)

firstly , we can find limit

\lim_{x \to 1-} f(x)=  \lim_{x \to 1-}(x+3)=1+3=4

\lim_{x \to 1+} f(x)=  \lim_{x \to 1-}(3x+1)=3*1+1=4

so, we get

\lim_{x \to 1} f(x)= 4

now, we can find f(1)

f(1)=3*1+1=4

so, we got

\lim_{x \to 1} f(x)=f(1) =4

so, this is continuous at x=1

Hence , option-D...........................Answer

5 0
3 years ago
The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

6 0
3 years ago
Read 2 more answers
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