The impulse that was produced by this aircraft jet engine is 5,400 Ns.
<u>Given the following data:</u>
To determine the impulse that was produced by this aircraft jet engine:
<h3>How to calculate
impulse.</h3>
Mathematically, impulse is given by this formula:
<u>Where:</u>
- F is the force or thrust.
- t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
Impulse, I = 5,400 Ns.
Read more on impulse here: brainly.com/question/16750406
<h3>
Answer:</h3>
1.25 < y < 8.32124...
<h3>
Step-by-step explanation:</h3>
The least y can be is the value that makes the angle in the smaller triangle be zero. (This condition will exist when the difference of side lengths is 4.)
... 4y -5 = 0
... y = 5/4 . . . . . add 5, divide by 4.
_____
The greatest y can be is the value obtained when the triangle is isosceles. For the larger triangle, that makes the side lengths (s) be ...
... 3/s = sin(43°/2)
... s = 3/sin(21.5°)
Then for the smaller triangle, that makes the angle be ...
... 4y -5 = arcsin(2/s) = arcsin(2/3·sin(21.5°))
... y = 1.25 + arcsin(2/3·sin(21.5°))/4
... y ≈ 8.32124
Answer:
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Step-by-step explanation: