$\bf \textit{volume of a cube}\\\\
V=s^3\qquad \boxed{s=\frac{s}{4}}\implies V=\left( \cfrac{s}{4} \right)^3\implies V=\cfrac{s^3}{4^3}\implies V=s^3\cdot \cfrac{1}{4^3}
\\\\\\
V=s^3\cdot \cfrac{1}{64}\impliedby \frac{1}{64}\textit{ of the original volume, if the original was 512}
\\\\\\
512\cdot \cfrac{1}{64}\implies \cfrac{512}{64}$

3 0

2 years ago

A 1.5m wire carries a 7 A current when a potential difference of 54 V is applied. What is the resistance of the wire?

borishaifa [10]

Answer:

R = 7.71 ohms

Step-by-step explanation:

By ohm's law: R= V/I

where, R = resistance of wire, V = potential difference, I = electric current

Given: V = 54 and I = 7 A

Plug in the above values in the ohm's law, we get

R = 54 V/7 A

R = 7.71 ohms

Hope this will helpful.

Thank you.

6 0

3 years ago

Read 2 more answers

(-4,9), (-4 -3), and (-1, 9) what is the area?

Gnesinka [82]

The area of it is 18

5 0

3 years ago