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3 years ago

Convert 9340 m to km

Mathematics

2 answers:

Marina CMI [18]3 years ago

7 0

Answer:

9.34 km

Step-by-step explanation:

m to km = m ÷ 1000
9340 ÷ 1000 = 9.34

I hope this helps!

ipn [44]3 years ago

6 0

Answer:

$9. 34$

Step-by-step explanation:

$M to KM \\1m = 0.001 KM\\9340M = 9.34 KM\\\\Hope \\ this \\helps$

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A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Write the name of the period that has the digits 913.

sergejj [24]

The name of period that has the digits 913 is hundreds.<span>
Because Period is considered to a group of places of the digits.</span>

In this case, the given number is 913 and it is the group of hundred because 900 is the highest number it contains.

We can also write 913 as

913 = 900 + 10 + 3

It means,

<span>9 hundreds + 10 tens + 3 ones</span>

8 0

3 years ago

Please help! will give brainliest:)

Lorico [155]

Answer

1) x = 8

2) x = 1/3y + -5/3z

3) x = -1/2y + -3/4z + -1/2

Hope this helps:))

7 0

2 years ago

A moving truck is rented at $1,000 per day plus a charge per hour of use. The moving truck was used for 9 hours one day, and the

Advocard [28]

1000 is our constant because the truck was only used one day. We also know they charge a certain amount per hour, but we do not know how much. In this case they charged that amount 9 times because the truck was used for 9 hours. The total of the constant plus the 9hour fee is 2700 dollars:

1000(1) + 9x = 2700

The reason we multiply 1000 by 1, is because we only used the truck for one day.

Solve for x

9x = 2700 - 1000 = 1700

X = 1700/9 = 188.88

The hourly fee is $188.88
The question is asking for an equation for hours of use though, so the answer is

1000(1) + 9(188.88) = C

C represents cost or charge.

4 0

4 years ago

Read 2 more answers

If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

(b)5,832 Mosquitoes

Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0

3 years ago

Read 2 more answers