12.) AM:MN is a 2:1 ratio. BN:AM is a 1:2 ratio. MN:AB is a 4:1 ratio.
13.) three equal parts: two-thirds m. five equal parts: four-fifths m.
![\sqrt[3]{\frac{-27x^9}{64y^{12}}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B-27x%5E9%7D%7B64y%5E%7B12%7D%7D%7D)
we take cube root separately
![\sqrt[3]{-27} =\sqrt[3]{-3*-3*-3} =-3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-27%7D%20%3D%5Csqrt%5B3%5D%7B-3%2A-3%2A-3%7D%20%3D-3)
We know cuberoot (x^3) is x
![\sqrt[3]{x^9}=\sqrt[3]{x^3*x^3*x^3}=x*x*x= x^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E9%7D%3D%5Csqrt%5B3%5D%7Bx%5E3%2Ax%5E3%2Ax%5E3%7D%3Dx%2Ax%2Ax%3D%20x%5E3)
![\sqrt[3]{64} =\sqrt[3]{4*4*4}= 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%5Csqrt%5B3%5D%7B4%2A4%2A4%7D%3D%204)
![\sqrt[3]{y^{12}} =\sqrt[3]{y^3*y^3*y^3*y^3}= y*y*y*y= y^4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E%7B12%7D%7D%20%3D%5Csqrt%5B3%5D%7By%5E3%2Ay%5E3%2Ay%5E3%2Ay%5E3%7D%3D%20y%2Ay%2Ay%2Ay%3D%20y%5E4)
![\sqrt[3]{\frac{-27x^9}{64y^{12}}}=\frac{-3x^3}{4y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B-27x%5E9%7D%7B64y%5E%7B12%7D%7D%7D%3D%5Cfrac%7B-3x%5E3%7D%7B4y%5E4%7D)
Here is the answer in comma-separated list.
(5, 10) , (10,15), (15, 20) (20, 25) (25, 300 (30, 35)
You need 5 dimes while having 10 or 25
2 semi circles form one full circle with a circumference of 68pi = 213.52
Rectangle has a perimeter of (68+108)*2 = 353
Total perimeter = 566.52m
Answer:
Solution given;
A(x1,y1)=(7,4)
B(x2,y2)=(-8,4)
distance AB=?
we have
d=
AB=
AB=15 units
the distance between the two points is 15 units.