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aalyn [17]
3 years ago
12

Solve for X Enter the answer in the box X=

Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

132

Step-by-step explanation:

The angles have to add up to 720

blondinia [14]3 years ago
3 0

Answer:

132  degrees

Step-by-step explanation:

The angles have to add up to 720 because all hexagons have 720 degrees.

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A
Semmy [17]

Step-by-step explanation:

y=75+50(36 hours)=1875

give me brainliest

4 0
3 years ago
using the midpoint formula, solve for the midpoint of the segment with these pairs of endpoints (-11,30) and (-26,-2)​
REY [17]

Answer:

Midpoint is (\frac{-37 }{2},  14)

Step-by-step explanation:

Midpoint = (\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

              = (\frac{-11 -26}{2}, \frac{30 - 2 }{2})

              =  (\frac{-37 }{2}, \frac{28 }{2})

              =  (\frac{-37 }{2},  14)

Midpoint is (-37/2, 14)

3 0
3 years ago
For a continuous random variable x, the height of the function at x is a. 0.50, since it is the middle value. b. a value less th
gogolik [260]

Answer:

Answer is a continuous random variable x the height of the function named the probability density function f(x)

Step-by-step explanation:

A continuous random variable takes infinite number of possible values.

example include  height , weight amount of sugar in an orange time required to run a mile.

Continues random variable named probability function f(x).

5 0
3 years ago
Round 75.4614 to the nearest thousandth
Anna11 [10]
75.4614\approx75.461
6 0
3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
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