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3 years ago

11

Dain and Sheryl's home sold for $751,150. They owe $657,900 on their mortgage. What will their net be after they pay $24,500 in

expenses and a 6.8% commission?

2 answers:

tatiyna3 years ago

7 0

Answer:

The net amount will be $17671.80.

Step-by-step explanation:

The selling price of the home = $751150

Mortgage payment = $657900

Expenses worth of = $24500

Now there is a 6.8% commission on sales price.

The commission is = $0.068\times751150=51078.20$

Price after commission remains = $751150-51078.20=700071.80$ dollars

Subtract the mortgage that has to be paid =

$700071.80-657900=42171.80$ dollars

Now, subtracting the expenses to get the net amount =

$42171.80-24500=17671.80$ dollars

Therefore, the net amount will be $17671.80.

Len [333]3 years ago

4 0

$751,150 -6.8%*751,150 -657,900 -24,500 = $17,671.80

Their net profit is $17,671.80.

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Reshma = x + 5
Reshma's father= 3x + 5

x + 5 + 3x + 5 = 70
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So Reshma's age currently is 15 and 3(15), which is 45, is her father's age.

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4 years ago

A restaurant served 315 meals. one third of the people ate a two-course meal while the remainder ate a three course meal. How ma

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Answer:

840 courses

Step-by-step explanation:

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3 years ago

(WITHIN 2 HOURS PLEASEEE!!)

goldfiish [28.3K]

Answer:

an average of 1.3 inches

Step-by-step explanation:

Using the mean absolute deviation, it can be concluded that the daily rainfall volume differs from the mean by an average of 1.3 inches.

What is the mean absolute deviation of a data-set?

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3 years ago

What's the correct equation?

alexgriva [62]

Answer:

C

Step-by-step explanation:

y=mx+b where m is the slope or weekly payments and b is the y-intercept or initial fee.

300 = 30w + 60 fits this

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2 years ago

A linear sequence starts a+3b a+7b a+11b the 2nd term has value 19 the 5th term has value 67 work out the values of a and b

alekssr [168]

Answer:

$a = -9$

$b = 4$

Step-by-step explanation:

Given

Sequence: a+3b, a+7b, a+11b

2nd term = 19

5th term = 67

Required

Find a and b

First, the 5th term needs to be calculated;

Using formula for Arithmetic Progression (AP), the formula goes thus

$T_n = T_1 + (n - 1)d$

Where n = 5

T_1 = a + 3b ------------ FIrst term

$d = T_2 - T_1 or T_3 - T_2$ --- Difference between two successive terms

$d = a + 7b - (a + 3b)$

$d = a + 7b -a - 3b$

$d = a - a + 7b - 3b$

$d = 4b$

So, $T_n = T_1 + (n - 1)d$ becomes

$T_5 = a + 3b + (5 - 1)4b$

$T_5 = a + 3b + (4)4b$

$T_5 = a + 3b + 16b$

$T_5 = a + 19b$

Now that we have values for 2nd and 5th term;

From the second, T2 = 19 and T5 = 67

This gives

$a + 7b = 19$ --- Equation 1

$a + 19b = 67$ ---- Equation 2

Make a the subject of formula in (1)

$a = 19 - 7b$

Substitute these values in equation 1

$a + 19b = 67$ becomes

$19 - 7b + 19b = 67$

$19 + 12b = 67$

Collect like terms

$12b= 67 - 19$

$12b = 48$

Divide both sides by 12

$\frac{12b}{12} = \frac{48}{12}$

$b = 4$

Recall that b = 4

Substitute a = 19 - 7b and nothing will hire

$a = 19 - 7(4)$

$a = 19 - 28$

$a = -9$

Hence, the values of a and b are -9 and 4 respectively.

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3 years ago