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3 years ago

Solve the equation. Use a calculator. c3 = 4 (Round to the nearest tenth as needed.)

1 answer:

6 0

To isolate the variable you would divide both sides of the equation by 3, resulting in the equation to answer c = 4/3 or c = 1.3

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Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94. The average of her last t

Bingel [31]

Answer: The average of the first two test scores is 97.

Step-by-step explanation: Given that Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94 and the average of her last three test scores is 92.

We are to find the average score of her first two tests.

Let a1, a2, a3, a4 and a5 be teh scores of Kristle in first , second, third, fourth and fifth tests respectively.

Then, according to the given information, we have

$\dfrac{a1+a2+a3+a4+a5}{5}=94\\\\\Rightarrow a1+a2+a3+a4+a5=94\times5\\\\\Rightarrow a1+a2+a3+a4+a5=470~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$\dfrac{a3+a4+a5}{3}=92\\\\\Rightarrow a3+a4+a5=92\times3\\\\\Rightarrow a3+a4+a5=276~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Subtracting equation (ii) from equation (i), we get

$(a1+a2+a3+a4+a5)-(a3+a4+a5)=470-276\\\\\Rightarrow a1+a2=194\\\\\Rightarrow \dfrac{a1+a2}{2}=\dfrac{194}{2}\\\\\Rightarrow \dfrac{a1+a2}{2}=97.$

Thus, the average of the first two test scores is 97.

6 0

3 years ago

Simplify the rational expression. state any restrictions on the variable. n^4-11n^2+30/n^4-7n^2+10

Andrej [43]

For this case we have the following expression:
 $\frac{n ^ 4-11n ^ 2 + 30}{ n ^ 4-7n ^ 2 + 10} 

$
 We are going to make the following change of variables:
 $x = n ^ 2
$
Rewriting the expression we have:
 $\frac{(x ^ 2-11x + 30)}{(x ^ 2-7x + 10)} 

$
Factoring the expression we have:
 $\frac{(x-5) (x-6)}{(x-5) (x-6)} 
$
Canceling similar terms we have:
 $\frac{x-6}{x-2} 
$
Returning the change we have:
 $\frac{n ^ 2-6}{n ^ 2-2} 

$
 The resctrictions of the function are those that make the denominator equal to zero.
We have then:
 $n ^ 2-2 = 0

n = +/- \sqrt{2} 
$
 Answer:
The simplified expression is:
 $\frac{n ^ 2-6}{n ^ 2-2}$
The restrictions are:
 $n = \sqrt{2} 
$
$n = - \sqrt{2}$

7 0

3 years ago

Kevin is 4 times as old as Daniel and is also 6 years older than Daniel. How old is Kevin?

tester [92]

Answer:

kevin = 8 - hope this helped

Step-by-step explanation:

Kevin = 4d Kevin is 4 times as old as Daniel

Kevin = d + 6 Kevin is 6 years older than Daniel

4d = d + 6 They both equal K, so they are equal

3d = 6 subtracts D from both sides

d=6/3 = 2

If Daniel is 2 then Kevin is 4x2=8

If Daniel is 2 then Kevin is 2+6 = 8

Kevin is 8

Daniel is 2

3 0

2 years ago

chegg tell whether each sequence is arithmetic. if the sequence os arithmetic, identify the common difference and find the indic

spin [16.1K]

No, the given sequence is not an arithmetic sequence.

What is Arithmetic Sequence ?

An arithmetic sequence is a list of numbers with a definite pattern. If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence.

In the above question,

The sequence is 3,5/2,3/2,-3/2,...

Take the 2nd term and minus the 1st term.

Now take the 3rd term and minus the 2nd term.

We can clearly notice that the differences are not same. Hence there is no common difference and therefore it's not an arithmetic sequence

To read about arithmetic sequence click here :

brainly.com/question/27079755

#SPJ4

5 0

1 year ago

RT has the endpoints (0, 2) and (4, 2). What is its midpoint?

Nimfa-mama [501]

R=(0,2), T=(4,2)
vector:
v=(4-0,2-2)=(4,0)
v/2=(2,0)

(0,2)+v/2=(2,2)

so (2,2) is the midpoint

3 0

3 years ago

Read 2 more answers

Solve the equation. Use a calculator. c3 = 4 (Round to the nearest tenth as needed.)​

Solve the equation. Use a calculator. c3 = 4 (Round to the nearest tenth as needed.)