Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
Answer: 1 mile.
Explanation: 1/2 of an hour is 1 mile because the speed was 2 miles an hour so if you do half of that it is 1 mile.
So the train is pulling about 50 cars in total, and there's about 30 boxes of freight in each car.
30 x 50 = 1500
The best estimate would be near 1500 boxes of freight through the whole train.
Answer:
6.66%
Step-by-step explanation:
((1 + r/m)^n) - 1
Interest rate , r = 6.5%
m = number of compounding times per period = 4 (quarterly interest)
((1 + 0.065/4)^4) - 1
((1 + 0.01625) ^4) - 1
((1.01625)^4) - 1
1.06660 - 1
= 0.0666
0.0666 * 100%
= 6.66%
Answer:
28
Step-by-step explanation: