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gladu [14]
3 years ago
9

Oki so this is the 3rd time ive asked this and i keep forgetting to put in the qeustion im very sorry

Mathematics
2 answers:
Zarrin [17]3 years ago
3 0

The answer is greater than one. :)

Vadim26 [7]3 years ago
3 0
7/6 so it's greater than haha
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Here is a system of equations. (y=x-6 y=-x-2 Graph the system. Then write its solution. Note that you can also answer "No soluti
sladkih [1.3K]

Answer:

Example system with no solution

We're asked to find the number of solutions to this system of equations:

\begin{aligned} y &= -3x+9\\\\ y &= -3x-7 \end{aligned}  

y

y

​  

 

=−3x+9

=−3x−7

​  

 

Without graphing these equations, we can observe that they both have a slope of -3−3minus, 3. This means that the lines must be parallel. And since the yyy-intercepts are different, we know the lines are not on top of each other.

There is no solution to this system of equations.

Example system with infinite solutions

We're asked to find the number of solutions to this system of equations:

\begin{aligned} -6x+4y &= 2\\\\ 3x-2y &= -1 \end{aligned}  

−6x+4y

3x−2y

​  

 

=2

=−1

​  

 

Interestingly, if we multiply the second equation by -2−2minus, 2, we get the first equation:

\begin{aligned} 3x-2y &= -1\\\\ \blueD{-2}(3x-2y)&=\blueD{-2}(-1)\\\\ -6x+4y &= 2 \end{aligned}  

3x−2y

−2(3x−2y)

−6x+4y

​  

 

=−1

=−2(−1)

=2

​  

 

In other words, the equations are equivalent and share the same graph. Any solution that works for one equation will also work for the other equation, so there are infinite solutions to the system.

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

6 0
3 years ago
Find the value of x in the given
iren2701 [21]

Answer:

You divide 62/12=5.166

5 0
3 years ago
Find x if AB = 9, BC = 2x - 5,<br> and AC = x + 9
Oxana [17]

Answer:

x = 5

Step-by-step explanation:

Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:

AB + BC = AC

Now, using the given values, we can substitute in for the equation and solve for x:

AB + BC = AC

9 + 2x - 5 = x + 9

2x + 4 = x + 9

x = 5

Thus, we have found that for these sets of equations for these line segments, our value for x should be 5.

Cheers.

5 0
3 years ago
Read 2 more answers
How can you order a ladder
NikAS [45]
An adult can go online and search for the kind of ladder needed.  Then they can choose the store they prefer.  After that, they would decide what payment method to use.  Shipping information would be entered, or they would go pick it up.  
3 0
3 years ago
Read 2 more answers
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