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DiKsa [7]
3 years ago
10

Find an angle in the normal range (0 degrees to 360 degrees, or 0 to 2pi radians) whose terminal side points in the same?directi

on as the terminal side of an angle measuring 560 degrees
​

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

Answer:

C. 200°

Step-by-step explanation:

560 - 360

200

Just add/subtract 360 (complete cycles) to get the angle in the normal range

EleoNora [17]3 years ago
4 0

560 degrees = 360 degrees + 200 degrees which is greater than 360 degrees.

For the terminal angle smaller than 360 degrees we have subtract 360 degrees from 560 degrees

560 - 360 = 200 degrees.

The answer is C. 200 degrees.

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discount per tshirt=(originalprice-discountedprice)/numberofshirtssold

20 tshirts

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discountedprice=20p-60

numberofshirtssold=20


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discountpershirt=(20p-20p+60)/20

discountpershirt=(60)/20

discountpershirt=3

the discount per tshirt is $3.00 per shirt

6 0
3 years ago
Read 2 more answers
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The correct equation is x=3 because there is no (Y) in the rise over run (y/x) meaning the starting point up and down the point on the (X) 
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3 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
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Answer:

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Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
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Answer:

= 4sqrt3

Step-by-step explanation:

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= -2i * i sqrt12 <-- i^2 = -1

= -2i^2sqrt12

= -2(-1)sqrt12

= 2sqrt12

= 2 * 2 sqrt3

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6 0
2 years ago
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X + y = 22
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this would be ur system of equations
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