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Novosadov [1.4K]
3 years ago
6

How would the expression x^3+64 be written using sum of cubes

Mathematics
2 answers:
Darya [45]3 years ago
8 0

Answer: (x+4)(x^2-4x+16)

Step-by-step explanation: APEX

Hunter-Best [27]3 years ago
4 0
\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\\\\
-------------------------------\\\\
\boxed{64=4^3}\qquad \qquad x^3+64\implies x^3+4^3\implies (x+4)(x^2-4x+16)
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Direct variation:-

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y=12 when x=6 so we have:-

12 = k*6

k = 12/6 = 2

so our equation of variation is  y = 2x Answer
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Andre45 [30]

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7 0
3 years ago
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Answer:

see explanation

Step-by-step explanation:

If A +B = 45° then tan(A+B) = tan45° = 1

Expanding (1 + tanA)(1 + tanB)

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Using the Addition formula for tan(A + B)

tan(A+B) = \frac{tanA+tanB}{1-tanAtanB} = 1 ← from above

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(1 + tanA)(1 + tanB) = 2 ⇒ proven

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