All categories

2 years ago

40÷{19−1+(6÷4−1)} PEMDAS form

Mathematics

1 answer:

Verdich [7]2 years ago

5 0

Answer & Step-by-step explanation:

PEMDAS:

Parentheses

Exponents

Multiplication and Division left to right

Addition and Subtraction left to right

We have two forms of grouping in the expression. Do the inner-most one first, still following PEMDAS within the grouping symbol:

Simplify division:

$6/4=1.5\\1.5-1=0.5\\$

Re-insert:

$40/(19-1+0.5)$

Simplify subtraction and addition within parentheses:

$19-1+0.5\\18+0.5\\18.5$

Re-insert:

$40/18.5$

Simplify division:

$40/18.5=2.162162162162162162.....$

:Done

You might be interested in

There were some people no a boat 26 people got off the boat at the first dock 22 people got off the boat now there ate 74 people

kramer

Answer:

Step-by-step explanation:

Let the initial number of people on the boat be x:

x - 26 - 22 = 74

x -48 = 74

x = 74 + 48

x = 122

Answered by G a u t h m a t h

7 0

2 years ago

What simple machine is similar to a pulley?

jek_recluse [69]

A lever in like a pully becasue it can pull just as so. Hope that helped. It is what my teacher taught me.

5 0

3 years ago

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one

Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that $p = 0.75$

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

$P(X = 6) + P(X < 6) = 1$