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Mrrafil [7]
4 years ago
11

Show that 999,973 is not prime without using a calculator or computer.

Mathematics
1 answer:
Alexxandr [17]4 years ago
5 0

Answer:

The number 9,99,973 is not prime number as 13, 61 and 97 are factors of 999973 apart from 1 and the number itself.

Step-by-step explanation:

We have to check whether 999973 is a prime number or not.

Prime factorization is a method where we break a number into product of prime numbers.

We first prime factorize the given number:

999973 = 13\times 13\times 61\times 97

Prime Number:

  • A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller numbers.
  • A natural number greater than 1 that is not prime is called a composite number.
  • Thus, a prime number cannot have factor other than 1 and the number itself.

Thus, we can say that the number 9,99,973 is not prime number as 13, 61 and 97 are factors of 999973 apart from 1 and the number itself.

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Answer:

2.25 or 2 1/4 hours each day

Step-by-step explanation:

To answer:

6 3/4 = 6.75

6.75 ÷ 3 = 2.25

So, Linda studied for 2.25 hours each day, or 2 1/4 hours each day

Hope this helps :)

5 0
3 years ago
14 ten thousands+12 thousands
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Charles and Lisa were having a watermelon eating contest. They ate twelve slices of watermelon between the two of them. Lisa ate
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Will do a brianly! ​Subtract.
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7 0
3 years ago
A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na
Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

v=\frac{d}{t}

where d is the total distance traveled and t is the total time needed.

d=\frac{4.00}{1.75}=2.29 km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0
3 years ago
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