Answer:
Option 2
Step-by-step explanation:
We know that the graph will face down (the negative sign)
We also know that the vertex should be (-2, 1)
Therefore, option 2 is the solution

- The name of the circle is <u>IJKL</u>
- The name of central Angle

- The name of the secant = <u>KL</u>
Circle :- It is a round figures, which has no end points.
Central angle :- It the angle ,which lie in the middle of the circle.
- Here, H is the mid point of the circle .So, Angle IHJ is the central angle.
Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .
- Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

- Semicircle = FGH and FIH
- Minor Arc :- FG or GH
- Major Arc :- FHG or GFH
Semicircle :- Semicircle is nothing but the half of the circle.
<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>
- FGH and FIH are acting as two semicircles which simulatineously forming one circle.
Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FG or GH are the minor arc of the given circle.
Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FHG or GFH is the major arc as it is larger than the semicircle of the given circle .
Answer:
x = 50
m∠D = 150°
m∠F = 30°
Step-by-step explanation:
- supplementary angles are two angles whose sum is 180°
∠D + ∠F = 180°
3x + x - 20 = 180
3x + x = 180 + 20
4x = 200
x = 200/4
x = 50
D = 3*50 = 150
∠D = 150°
F = 50 - 20 = 30
∠F = 30°
Answer:
this is the answer
Step-by-step explanation:
The answer is 0 < x <span>≤ 7
</span>
First, we know that width = x
Which means that length = x +18
So, the possible equation for the Table's area is
X (X + 18) ≤ 175
X^2 + 18x - 175 <span>≤ </span>0
Next, we need to calculate is by using complete square method
x^2 + 18x + 81 <span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
Since the width couldn't be negative, we can change -25 with 0,
so it become
</span> 0 < x ≤ 7