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3 years ago

15

The troposphere extends from the earths surface to a height of 6-12 miles depending on the location and the season. If a plane i

s flying at an altitude of 5.8 miles and the troposphere is 8.6 miles drop in that ears how much higher can the plane go without leaving the troposphere

1 answer:

Vika [28.1K]3 years ago

6 0

Answer:

2.8

Step-by-step explanation:

8.6 - 5.8

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Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

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3 years ago

A box contains 20 miniature golf putt-putt balls; 10 are

stellarik [79]

Answer: The answer is provided below

Step-by-step explanation:

From the question, a box contains 20 miniature golf putt-putt balls out of which 10 are yellow, 6 are red, and the remaining 4 are pink.

The probability of picking a red golf ball will be:

= 6/20 × 100

= 600/20

= 30%

If the red ball is replaced, the probability of picking a yellow golf ball will be:

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3 years ago

The figure is made up of a hemisphere and a cylinder.

Goryan [66]

Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: $\pi \approx 3.14$
V (volume) = ?

Solving:(<span>Cylinder volume)
</span> $V = h* \pi *r^2$
$V = 8*3.14*5^2$
$V = 8*3.14*25$
$\boxed{ V_{cylinder} = 628\:cm^3}$

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4 * \pi * \frac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3} 
$

Formula: (<span>Volume of the hemisphere)
</span> $V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}$

Solving:
$V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}$
$V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}$
$V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}$
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<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
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$\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark$

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3 years ago

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Doss [256]

Answer:

Step-by-step explanation:

multiply x as a negative.

Example:

f(x) = 3x + 1

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f(-x) = -3x + 1

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3 years ago

A spotlight is made by placing a strong light bulb inside a reflective paraboloid formed by rotating the parabola x^2=4y around

Nadya [2.5K]

Answer:

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The distance from vertex to focus is "p" in the quadratic equation ...

x^2 = 4py

In the given equation, p=1. Since units are inches, ...

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