4 years ago

Write quadratic equation in standard form with given solution set: {1/6, -2/3} ...?

1 answer:

5 0

(x - 1/6)(x - (-2/3)) = 0
(x - 1/6)(x + 2/3) = 0
x^2 + 2/3x - 1/6x - 1/6(2/3) = 0
x^2 + 1/2x - 1/9 = 0
18x^2 + 9x - 2 = 0

You might be interested in

To put up several tents for a camping trip, you need several pieces of rope each 6 2/3 feet long. If you have a rope that is 43

Otrada [13]

$\bf 43\div 6\frac{2}{3}\implies \cfrac{46}{6\frac{2}{3}}\implies \cfrac{\frac{46}{1}}{\frac{6\cdot 3+2}{3}}\implies \cfrac{\frac{46}{1}}{\frac{20}{3}} \implies \cfrac{46}{1}\cdot \cfrac{3}{20}\implies \cfrac{69}{10}
\\\\\\
\boxed{6\frac{9}{10}}\qquad \qquad 
\cfrac{6\cdot 10+9}{10}\implies \cfrac{69}{10}$