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3 years ago

9

What is 78.74 rounded to the nearest hundredths

2 answers:

loris [4]3 years ago

7 0

It is 100.00 or just 100

nikdorinn [45]3 years ago

6 0

78.74 because there is a zero behind 4 and 0 is less than 5 so it stays the same

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Can you please answer this question it’s easy points!!!

scZoUnD [109]

Answer:

Step-by-step explanation:

I think that you have to multiply 82.18 times 2 to see how many dollars it costs.

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4 years ago

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A line passes through the points (4,6) and (6,2) .

siniylev [52]

ANSWER

Yes

No

No

Yes

EXPLANATION

The given line passes through the points,.
$(4,6) \: and \: (6,2)$

We need to determine the slope of this line using these two points.

The formula for finding the slope is

$m=\frac{y_2-y_1}{x_2-x_1}$

$m = \frac{2 - 6}{6 - 4} = - \frac{ - 4}{2} = - 2$

We can now use the formula

$y-y_1=m(x-x_1)$
in the slope intercept form.

If we use the point
$(4,6)$
the equation will be,

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If we use the point,

$(6,2)$
we obtain,
$y - 2 = - 2(x - 6)$

6 0

3 years ago

Read 2 more answers

22 less than the quotient of an unknown number and 35 is -25.

Agata [3.3K]

-22+(x/35)=-25
add 22 to both sides
x/35=-3
multiply both sides by 35 to cleaf raction
x=-105

number was -105

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4 years ago

Each algorithm is applied to a group of 52 sample problems. The new algorithm completes the sample problems with a mean time of

dem82 [27]

Answer:

Therefore we fail to reject the Null hypothesis $H_0$

Because the is no sufficient evidence to support the claim of the alternative hypothesis $H_a$

Step-by-step explanation:

From the question we are told that

Sample size $n_1 =52$

Mean time 1 $\=x_1=24.04\ hours$

Mean time 2 $\=x_2=24.52\ hours$

Standard deviation $\partial _1=5.769$

Standard deviation $\partial _2=5.556$

Level of significance 0.05

The null hypothesis is $H_o: \mu_1=\mu_2$

Alternative hypothesis $H_a: \mu_1$

Generally the test statistics is mathematically represented as

$Z= \frac{\=x_1-\=x_2}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}$

$Z= \frac{24.04-24.52}{\sqrt{\frac{5.769^2}{52}+\frac{5.5562^2}{52}}}$

$Z= -0.4321583379$

$Z= -0.43$

From Table the Z-critical value at $\alpha =0.05\ is\ -1.6449$

Therefore

Zcal> Zcritical

(-0.43)=(-1.645)

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Therefore we fail to reject the $H_0$

Because the is no sufficient evidence to support the claim of $H_a$

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3 years ago

Kathy swims at least 6 laps every day. Write an

umka2103 [35]

Step-by-step explanation:

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4 years ago