You can do this by finding the lengths of RT , RS and ST using the distance formula
RT = sqrt ((0- -5)^2 + (4 - -6)^2)
= sqrt (5^2 + 10^2) = sqrt 125
RS = sqrt ((-3- -5)^2 + (-2 - -6)^2))
= sqrt ( 2^2 + 4^2) = sqrt 20
ST = sqrt 125 - sqrt 20
RS / ST = sqrt 20 / (sqrt 125-sqrt 20)
so the ratio RS:ST = 2:3
Its B
Answer:
x=61 -> Figure A
x=27 -> Figure B
x=12 -> Figure C
Step-by-step explanation:
<u>For A:</u>
<u>x=61</u> because the line going through the shape cuts in angle into 2 congruent angles
<u>For B:</u>
The corner adds up to 90 because it a rectangle, and rectangles only have right angles.
So: 2x+10+x-1=90
Solve.
3x+9=90
3x=81
<u>x=27</u>
<u>For C:</u>
The two given angles should add up to 90.
4x+10+2x+8=90
Solve.
6x+18=90
6x=72
<u>x=12</u>
Remember
a^3-b^3=(a-b)(a^2+ab+b^2)
(11x)³-(2y)³=(11x-2y)(121x²+22xy-4y²)
The standard form for the equation of a circle is :
<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :
((−10+(−8))/2,(1+5)/2)=(−9,3)
So the point (−9,3) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(−10−(−9))^2+(1−3)^2=1+4=5
⇒r=√5
Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :
(x+9)^2+(y−3)^2=5
4×754=3016
4×4=16 4×5=20+1 4×7=30
this is the first method I mean this is the method that we are useing here in Macedonia
or maybe 754×4